http://stackoverflow.com/questions/24753821/php-fopen-error-handling
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I do fetch a file with
$fp = fopen('uploads/Team/img/'.$team_id.'.png', "rb");
$str = stream_get_contents($fp);
fclose($fp);
and then the method gives it back as image. But when fopen() fails, because the file did not exists, it throws an error:
[{"message":"Warning: fopen(uploads\/Team\/img\/1.png): failed to open stream: No such file or directory in C:\...
This is coming back as json, obviously.
The Question is now: How can i catch the error and prevent the method from throwing this error directly to the client?
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You should first test the existence of a file by file_exists().
try
{
$fileName = 'uploads/Team/img/'.$team_id.'.png';
if ( !file_exists($fileName) ) {
throw new Exception('File not found.');
}
$fp = fopen($fileName, "rb");
if ( !$fp ) {
throw new Exception('File open failed.');
}
$str = stream_get_contents($fp);
fclose($fp);
// send success JSON
} catch ( Exception $e ) {
// send error message if you can
}
or simple solution without exceptions:
$fileName = 'uploads/Team/img/'.$team_id.'.png';
if ( file_exists($fileName) && ($fp = fopen($fileName, "rb"))!==false ) {
$str = stream_get_contents($fp);
fclose($fp);
// send success JSON
}
else
{
// send error message if you can
}
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answered Jul 15 '14 at 9:10
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if($fp = fopen('uploads/Team/img/'.$team_id.'.png', "rb")){ throw this->createNotFoundException('No image found for id '.$team_id); }but it didnt worked. – humpdi Jul 15 '14 at 8:54try { $fp = fopen('uploads/Team/img/'.$team_id.'.png', "rb"); } catch(Exception $e) { throw $this->createNotFoundException('No image found for id '.$team_id); }– humpdi Jul 15 '14 at 8:58